2x^(2/3)-5x^(1/3)=0

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Solution for 2x^(2/3)-5x^(1/3)=0 equation: 


x in (-oo:+oo)

2*x^(2/3)-(5*x^(1/3)) = 0

2*x^(2/3)-5*x^(1/3) = 0

t_1 = x^(1/3)

2*t_1^2-5*t_1^1 = 0

2*t_1^2-5*t_1 = 0

DELTA = (-5)^2-(0*2*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)+5)/(2*2) or t_1 = (5-25^(1/2))/(2*2)

t_1 = 5/2 or t_1 = 0

t_1 = 0

x^(1/3)+0 = 0

x^(1/3) = 0

1*x^(1/3) = 0 // : 1

x^(1/3) = 0

x = 0

t_1 = 5/2

x^(1/3)-5/2 = 0

1*x^(1/3) = 5/2 // : 1

x^(1/3) = 5/2

x^(1/3) = 5/2 // ^ 3

x = 125/8

x in { 0, 125/8 }

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